Appendix F: Answers to Problems
Chapter1
Chapter2
Chapter3
Chapter4
Chapter5
Chapter6
Chapter7
Chapter8
Chapter9
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Chapter 1:
1. Fastball t = 0.45 sec; curveball t = 0.68
sec
2. t = 0.2 sec
4. u =
5.45 m/sec = 12mph
5. Johnson u = 95.01 ft/sec; Mueller u = 94.77
ft/sec
6. a. At the 70 meter mark
7. a = 3 ft/sec2
d = 150 ft
8. b. Distance traveled while reacting = 70.4 ft
c. Distance traveled while stopping =
193.6 ft
d.
Total distance needed to stop = 264 ft
9. a. d = 45 m
b. t = 3 seconds
c. t = 6 seconds
d. v = 30 m/sec, down
10. t = 1 sec: d = 15 m, v = 10 m/sec, up
t = 2 sec: d = 20 m, v = zero
t = 3 sec: d = 15 m, v = 10
m/sec, down
t = 4 sec: d = 0, v = 20 m/sec,
down
t = 5 sec: d = -25 m, v = 30
m/sec, down
11. v = 32 ft/sec
t = 1 sec
12. a. t = 0.47 sec
b. t = 0.35 sec
1. t = 0.5 seconds, x = 2.0 meters
2. t = 4 seconds, y = 80 meters
3. y = 4 ft
4. a. y
= 0.81 ft
b. y = 3.24 ft
c. y = 2.43 ft
5. a. vIx
= 86.6 m/sec b.
vIx = 70.7 m/sec c.
vIx = 50 m/sec
vIy = 50 m/sec vIy = 70.7 m/sec vIy = 86.6 m/sec
6. a. vx
= 2.4 m/sec
b. vy = 6.6 m/sec
c. y = 2.2 meters = 7.1 ft
7. a. vIx
= 40 m/sec, vIy = 30 m/sec
b. y = 45 meters
c. t = 3 seconds
d. v = 40 m/sec in the horizontal direction
e. a = g = 10 m/sec2, down
f. t = 6 seconds
g. R = 240 meters
8. R = 517 ft = 172 yd
9. a. h
= 41 ft
b. h = 176 ft
10. vI = 121 ft/sec
11. v = 38 ft/sec
1. F = 200 N
2. W = 170 N
3. m = 7 slugs
6. F = 35 lb
7. m = 5 slugs, W = 160 lb
8. a. a
= 111 m/sec2
b. F = 7770 N = 1746 lb
c. F = 1665 N = 374 lb
9. a = 6 m/sec2
b. W = 500 N
c. Force parallel = 300 N
d. R = 400 N
e. Zero
10. a. Fnet = 25 N, right
Block accelerates
b. Fnet = 0
Block moves with
constant acceleration
c. Fnet = 25 N, left
Block decelerates
11. W = 500 lb
12. Kinetic frictional force, the normal force,
and the puck’s weight.
13. a. Fs
= 5 N
b. R = 20 N
c. ms =
0.25
14. F = 51.8 lb
15. a. F
= 51.8 lb
b. F = 100 lb
1. The 20 kg object
2. a.
Change in momentum = 6 N•sec
b. Impulse = 6 N•sec
c. F = 120 N = 27 lb
3. a.
Change in momentum = 15 N•sec
b. Impulse = 15 N•sec
c. F = 6000 N = 1350 lb
4. v = 20 mph
5. a. m = 5 slugs
b. v = 8 ft/sec
c. Impulse = 40 lb•sec
d. t = 0.0125 sec
e. F = 3200 lb
6. v = 9.6 ft/sec
7. v = 5.3 ft/sec
9. h = 0.58 m
1. Work = 350 J. If t = 1 sec, P = 350 Watts; if t= 10 sec, P = 35 Watts
2. Work = 4000 J
3. Work = 9000 J, t = 9 seconds
4. a.
87 ft•lbs
b. 87 ft•lbs
c. 522 lbs
5. a.
Work = 625 J
b. Work = 1600 J – 625 J – 975 J
6. d = 200 feet
7. h – 121 feet
8. v = 21 ft/sec
9. v = 10 m/sec
10. h = 0.45 m
1. q = 6p
radians = 1080 degrees
2. q = 2 radians = 0.32 revolutions
= 114.6 degrees
3. w = 3.33 rev/sec = 20.9
rad/sec
4. q = 0.56 rev
5. a = -0.022 rev/sec2,
q = 7.28 rev
6. wI =
1.2 rev/sec = 72 rpm
7. wF = 20
rad/sec, q= 100 rad = 16 rev
8. s = 40 m, v = 8 m/sec, a = 0.8 m/sec2
9. Nine-iron:
v = 15 ft/sec
Driver: v = 20 ft/sec
10. w = 57 rad/sec = 9
rev/sec
11. F = 209.5 N
12. F = 8000 N = 1798 lbs
13. a = 12.5 m/sec2; F = 875 N
14. w = 3.17 rad/sec = 0.5
rev/sec
1. a.
600 ft•lb
b. 1400 N•m
c. 300 ft•lb
d. zero
2. 4 feet from the center of the seesaw.
3. x = 4 feet
4. Force exerted by the Achilles = 514 lb;
Force on the tibia = 714 lb
5. F = 100 lb
6. W = 6 lb
8. a.
33 lb
b. 67 lb
c. 20 lb
9. I = 0.5 kg/m2; Torque = 4 N•m
10. a. I
= 10 kg•m2
b. I = 26.7 kg•m2
c. w = 0.75 rev/sec
12. a. I
= 600 kg•m2
b. w = 0.75 rev/sec
13. a. I
=0.045 kg•m2
b. w = 26.7 rad/sec
c. KEROT = 16 J
d. KETRANS = 40 J
e. KETOT = 56 J
14. h = 1.6 m
1. m = 3800 g; W = 8.36 lb
2. d = 7.93 g/cm3
3. If your mass is 70 kg, then your volume
would be 70 liters.
4. If your volume is 70 liters, then 14.3
similar people could fit into a 1 m3 box.
5. Without a helmet the pressure is 50 times greater.
6. P = 13 N/cm2
7. P = 5.7 lb/in2
8. P = 161.9 Atmospheres = 2380 lb/in2
9. The bubbles become larger.
10. h = 0.5 m
11. P = 19,000 N/m2 = 144 mm of
mercury
12. This is the same level as your heart.
13. h = 0.76 m = 76 cm = 30 inches
14. h = 10 meters
15. F = 50 lb
16. F = 20 N
17. a. W
= 700 N
b. V = 0.067 m3
c. V = 0.067 m3
d. m = 67 kg
e. BF = 670 N
f. Apparent weight = 30 N = 6.4 lb
18. 92 percent.
Less of the iceberg would be submerged in seawater.
1. a. v
= 12 m/sec
b. P = 132, 500 N/m2
c. same
2. v = 12.5 m/sec
3. m/t = 88 g/sec
4. v = 26.5 cm/sec
5. v = 41.4 cm/sec
6. P1 – P2 = 53.6 N/m2
8. a.
P1 – P2 = 8060 N/m2
F = 64,480 N = 14, 490 lbs