Appendix F:  Answers to Problems


Chapter1

Chapter2
Chapter3
Chapter4
Chapter5
Chapter6
Chapter7
Chapter8
Chapter9
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Chapter 1:

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1.  Fastball t = 0.45 sec; curveball t = 0.68 sec

2.  t = 0.2 sec

4.  u  = 5.45 m/sec = 12mph

5.  Johnson u = 95.01 ft/sec; Mueller u = 94.77 ft/sec

6. a.  At the 70 meter mark

7. a = 3 ft/sec2

d = 150 ft

8. b.  Distance traveled while reacting = 70.4 ft

    c. Distance traveled while stopping = 193.6 ft

    d.  Total distance needed to stop = 264 ft

9. a.   d = 45 m

b. t = 3 seconds

c. t = 6 seconds

d. v = 30 m/sec, down

10.           t = 1 sec: d = 15 m, v = 10 m/sec, up

                t = 2 sec: d = 20 m, v = zero

                t = 3 sec: d = 15 m, v = 10 m/sec, down

                t = 4 sec: d = 0, v = 20 m/sec, down

                t = 5 sec: d = -25 m, v = 30 m/sec, down

11. v = 32 ft/sec

t = 1 sec

12. a. t = 0.47 sec

b.  t = 0.35 sec

 

Chapter 2:

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1.  t = 0.5 seconds, x = 2.0 meters

2.  t = 4 seconds, y = 80 meters

3.  y = 4 ft

4.  a.  y = 0.81 ft

b.  y = 3.24 ft

c.  y = 2.43 ft

5.  a.  vIx = 86.6 m/sec                           b. vIx = 70.7 m/sec                                c. vIx = 50 m/sec

          vIy = 50 m/sec                                  vIy = 70.7 m/sec                                    vIy = 86.6 m/sec

6.  a.  vx = 2.4 m/sec

b.  vy = 6.6 m/sec

c.  y = 2.2 meters = 7.1 ft

7.  a.  vIx = 40 m/sec, vIy = 30 m/sec

b.  y = 45 meters

c.  t = 3 seconds

d.  v = 40 m/sec in the horizontal direction

e.  a = g = 10 m/sec2, down

f.  t = 6 seconds

g.  R = 240 meters

8.  R = 517 ft = 172 yd

9.  a.  h = 41 ft

b.  h = 176 ft

10.  vI = 121 ft/sec

11.  v = 38 ft/sec

 

Chapter 3:

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1.  F = 200 N

2.  W = 170 N

3.  m = 7 slugs

6.  F = 35 lb

7.  m = 5 slugs, W = 160 lb

8.  a.  a = 111 m/sec2

b.  F = 7770 N = 1746 lb

c.  F = 1665 N = 374 lb

9.  a = 6 m/sec2

b.  W = 500 N

c.  Force parallel = 300 N

d.  R = 400 N

e.  Zero

10.  a. Fnet = 25 N, right

Block accelerates

b.  Fnet = 0

Block moves with constant acceleration

c.  Fnet = 25 N, left

Block decelerates

11.  W = 500 lb

12.  Kinetic frictional force, the normal force, and the puck’s weight.

13.  a.  Fs = 5 N

b.  R = 20 N

c.  ms = 0.25

14.  F = 51.8 lb

15.  a.  F = 51.8 lb

b.  F = 100 lb

 

Chapter 4:

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1.  The 20 kg object

2.  a.  Change in momentum = 6 N•sec

b.  Impulse = 6 N•sec

c.  F = 120 N = 27 lb

3.  a.  Change in momentum = 15 N•sec

b.  Impulse = 15 N•sec

c.  F = 6000 N = 1350 lb

4.  v = 20 mph

5.  a. m = 5 slugs

b.  v = 8 ft/sec

c.  Impulse = 40 lb•sec

d.  t = 0.0125 sec

e.  F = 3200 lb

6.  v = 9.6 ft/sec

7.  v = 5.3 ft/sec

9.  h = 0.58 m

 

Chapter 5:

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1.  Work = 350 J.  If t = 1 sec, P = 350 Watts; if t= 10 sec, P = 35 Watts

2.  Work = 4000 J

3.  Work = 9000 J, t = 9 seconds

4.  a.  87 ft•lbs

b.  87 ft•lbs

c.  522 lbs

5.  a.  Work = 625 J

b.  Work = 1600 J – 625 J – 975 J

6.  d = 200 feet

7.  h – 121 feet

8.  v = 21 ft/sec

9.  v = 10 m/sec

10. h = 0.45 m

 

Chapter 6:

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1.  q = 6p radians = 1080 degrees

2.  q = 2 radians = 0.32 revolutions = 114.6 degrees

3.  w = 3.33 rev/sec = 20.9 rad/sec

4.  q = 0.56 rev

5.  a = -0.022 rev/sec2, q = 7.28 rev

6.  wI = 1.2 rev/sec = 72 rpm

7.  wF = 20 rad/sec, q= 100 rad = 16 rev

8.  s = 40 m, v = 8 m/sec, a = 0.8 m/sec2

9.  Nine-iron:  v = 15 ft/sec

Driver:  v = 20 ft/sec

10.  w = 57 rad/sec = 9 rev/sec

11.  F = 209.5 N

12.  F = 8000 N = 1798 lbs

13.  a = 12.5 m/sec2; F = 875 N

14.  w = 3.17 rad/sec = 0.5 rev/sec

 

Chapter 7:

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1.  a.  600 ft•lb

b.  1400 N•m

c.  300 ft•lb

d.  zero

2.  4 feet from the center of the seesaw.

3.  x = 4 feet

4.  Force exerted by the Achilles = 514 lb; Force on the tibia = 714 lb

5.  F = 100 lb

6.  W = 6 lb

8.  a.  33 lb

b.  67 lb

c.  20 lb

9.  I = 0.5 kg/m2; Torque = 4 N•m

10.  a.  I = 10 kg•m2

b.  I = 26.7 kg•m2

c.  w = 0.75 rev/sec

12.  a.  I = 600 kg•m2

b.  w = 0.75 rev/sec

13.  a.  I =0.045 kg•m2

b.  w = 26.7 rad/sec

c.  KEROT = 16 J

d.  KETRANS = 40 J

e.  KETOT = 56 J

14.  h = 1.6 m

 

Chapter 8:

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1.  m = 3800 g; W = 8.36 lb

2.  d = 7.93 g/cm3

3.  If your mass is 70 kg, then your volume would be 70 liters.

4.  If your volume is 70 liters, then 14.3 similar people could fit into a 1 m3 box.

5.  Without a helmet the pressure is 50 times greater.

6.  P = 13 N/cm2

7.  P = 5.7 lb/in2

8.  P = 161.9 Atmospheres = 2380 lb/in2

9.  The bubbles become larger.

10.  h = 0.5 m

11.  P = 19,000 N/m2 = 144 mm of mercury

12.  This is the same level as your heart.

13.  h = 0.76 m = 76 cm = 30 inches

14.  h = 10 meters

15.  F = 50 lb

16.  F = 20 N

17.  a.  W = 700 N

b.  V = 0.067 m3

c.  V = 0.067 m3

d.  m = 67 kg

e.  BF = 670 N

f.  Apparent weight = 30 N = 6.4 lb

18.  92 percent.  Less of the iceberg would be submerged in seawater.

 

Chapter 9:

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1.  a.  v = 12 m/sec

b.  P = 132, 500 N/m2

c.  same

2.  v = 12.5 m/sec

3.  m/t = 88 g/sec

4.  v = 26.5 cm/sec

5.  v = 41.4 cm/sec

6.  P1 – P2 = 53.6 N/m2

8.  a.  P1 – P2 = 8060 N/m2

F = 64,480 N = 14, 490 lbs